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Next: b) Collective model: Up: 3 Basic theory and Previous: 3.2.0.1 Example 2: 19F+28Si

Example 2: CC with cluster form factors


Test run: CC calculation 19F+28Si. Cluster form factors            
NAMELIST
 &FRESCO hcm=0.100 rmatch=25.000 rintp=0.50 
	 hnl=0.100 rnl=3.00 centre=0.00 jtmin=0.0 jtmax=80.0 
	 absend=0.0100 dry=F thmin=0.00 thmax=60.00 
	 thinc=2.50 ips=0.0000 iter=1 iblock=2 pralpha=F 
	 nnu=30 chans=1 listcc=2 smats=1  pel=1 exl=1 
	 lab=1 lin=1 lex=1 elab=60.0  
	 fatal=T nosol=F psiren=F unitmass=1.007335 
	 finec=137.03599  /

 &PARTITION namep='19-F' massp=19 zp=9 namet='28-SI' 
	 masst=28 zt=14 qval=0.0000 pwf=T nex=2  /
 &STATES jp=0.5 bandp=1 ep=0.0000 cpot=1 jt=0.0 
	 bandt=1 et=0.0000 fexch=F  /
 &STATES jp=2.5 bandp=1 ep=0.2000 jt=0.0 et=0.0000 
	 fexch=F  /

 &PARTITION namep='16-O' massp=16 zp=8 namet='31-P' 
	 masst=31 zt=15 qval=6.1990 pwf=T nex=1  /
 &STATES jp=0.0 bandp=1 ep=0.0000 jt=0.5 bandt=1 
	 et=0.0000 fexch=F  /
 &partition /
 
 &POT kp=1 itt=F ap=28.000 at=19.000 rc=1.200  /
 &POT kp=2 itt=F ap=31.000 at=16.000 rc=1.350  /
 &POT kp=2 type=1 itt=F p1=31.200 p2=1.450 
	 p3=0.470 p4=15.100 p5=1.270 p6=0.310 p7=0.000  /
 &POT kp=2 type=3 itt=F p1=0.750 p2=1.240 p3=0.370  /
 &POT kp=3 itt=F ap=19.000 at=0.000 rc=1.250 
	 ac=0.650  /
 &POT kp=3 type=1 itt=F p1=115.000 p2=1.250 
	 p3=0.650  /
 &POT kp=3 type=3 itt=F p1=6.300 p2=1.250 p3=0.650  /
 &POT kp=4 itt=F ap=31.000 at=0.000 rc=1.250 
	 ac=0.650  /
 &POT kp=4 type=1 itt=F p1=99.000 p2=1.250 
	 p3=0.650  /
 &POT kp=4 type=3 itt=F p1=6.300 p2=1.250 p3=0.650  /
 &POT kp=5 itt=F ap=28.000 at=0.000 rc=1.200  /
 &POT kp=5 type=1 itt=F p1=27.000 p2=2.425 
	 p3=0.460 p4=11.660 p5=2.145 p6=0.238 p7=0.000  /
 &POT kp=6 itt=F ap=28.000 at=0.000 rc=1.250 
	 ac=0.650  /
 &POT kp=6 type=1 itt=F p1=160.000 p2=1.070 
	 p3=0.720 p4=37.000 p5=1.350 p6=0.880 p7=0.000  /
 &pot / 
 
 &OVERLAP kn1=1 ic1=1 ic2=2 in=1 nn=4 sn=0.5 j=0.5 
	 kbpot=3 be=11.7300 isc=1 nam=1 ampl=1.0000  /
 &OVERLAP kn1=2 ic1=1 ic2=2 in=1 nn=3 l=2 sn=0.5 
	 j=2.5 kbpot=3 be=11.5300 isc=1 nam=1 ampl=1.0000  /
 &overlap / 
 
 &COUPLING icto=1 icfrom=2 kind=3 ip1=4 ip2=1 
	 p1=6.0000 p2=5.0000 jmax=0.00 rmax=0.0  /
 &CFP in=1 ib=1 ia=1 kn=1 a=1.000  /
 &CFP in=1 ib=2 ia=1 kn=2 a=1.000  /
 &cfp / 
 
 &coupling / 
 



Antonio Moro 2004-10-27